SOLUTION: Find the minor axis vertices of the ellipse.16x^2+4y^2+64x+24y+36=0

Question 548197: Find the minor axis vertices of the ellipse.16x^2+4y^2+64x+24y+36=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the minor axis vertices of the ellipse.16x^2+4y^2+64x+24y+36=0
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16x^2+4y^2+64x+24y+36=0
complete the square
16(x^2+4x+4)+4(y^2+6y+9)=-36+64+36
16(x+2)^2+4(y+3)^2=64
divide by 64
(x+2)^2/4+(y+3)^2/16=1
This is an equation of an ellipse with vertical major axis of the standard form:
(x-h)^2/b^2+(y-k)^2/a^2=1, a>b, with (h,k) being the (x,y) coordinates of the center.
..
For given ellipse:
center:(-2,-3)
b^2=4
b=√4=2
Vertices of minor axis=(-2�b,-3)=(-2�2,-3)=(-4,-3) and (0,-3)
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