# SOLUTION: Given the focus of the parabola (0,-6), and the directirx y=6, find the equation of the parabola.

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 Question 546684: Given the focus of the parabola (0,-6), and the directirx y=6, find the equation of the parabola.Answer by lwsshak3(6519)   (Show Source): You can put this solution on YOUR website!Given the focus of the parabola (0,-6), and the directirx y=6, find the equation of the parabola. ** Since the focus is below the directrix on the axis of symmetry,(x=0), this is a parabola which opens downward. Its standard form of equation: (x-h)^2=-4p(y-k), (h,k) being the (x,y) coordinates of the vertex: .. For given parabola: y-coordinate of vertex=half-way between directrix and focus on axis of symmetry=0 x-coordinate of vertex=0 vertex: (0,0) p=distance from vertex to focus or to directrix on the axis of symmetry=6 Equation of given parabola: (x-0)^2=-4p(y-0) x^2=-24y (ans)