SOLUTION: This is about parabola's. I know the fomula to find the vertex is y=aX^2+bx+c But I dont understand the process of working the problem out. The equation is y=(x-2)^2+3 (I don

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: This is about parabola's. I know the fomula to find the vertex is y=aX^2+bx+c But I dont understand the process of working the problem out. The equation is y=(x-2)^2+3 (I don      Log On


   

Question 546624: This is about parabola's.
I know the fomula to find the vertex is y=aX^2+bx+c
But I dont understand the process of working the problem out.
The equation is y=(x-2)^2+3
(I dont have the raised to 2nd power key so I put ^2 hope its not a problem)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
This is about parabola's.
I know the fomula to find the vertex is y=aX^2+bx+c
But I dont understand the process of working the problem out.
The equation is y=(x-2)^2+3
**
Standard form of equation for a parabola which opens upwards: y=A(x-h)^2=k, with (h,k) being the (x,y) coordinates of the vertex.
Given equation is already in standard form from which you can read the vertex.
Vertex: (2,3)