SOLUTION: which equation gives the directrix of y-1/12x^2-5? y=-8 y=3 x=3 y=-5 please need help for math class.

Question 545235: which equation gives the directrix of y-1/12x^2-5?
y=-8
y=3
x=3
y=-5
please need help for math class.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
which equation gives the directrix of y-1/12x^2-5?
y=-8
y=3
x=3
y=-5
**
I think you meant to write the equation as:y=(1/12)x^2-5
Which can be rewritten as: (1/12)x^2=y+5 or x^2=12(y+5)
This equation is of the standard form: (x-h)^2=4py, with (h,k) being the (x,y) coordinates of the vertex.
..
For given equation:
vertex: (0,-5)
Axis of symmetry: x=0 or y-axis (parabola opens upwards)
4p=12
p=3
The directrix is p units below the vertex on the axis of symmetry
Equation of Directrix: y= -8
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