SOLUTION: what is the minimum value of the equation y=1/3x^2+2x+5
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Question 544865: what is the minimum value of the equation y=1/3x^2+2x+5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
what is the minimum value of the equation y=1/3x^2+2x+5
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The minimum occurs when x = -b/(2a) = -2/(2/3) = -3
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f(-3) = (1/3)(-3)^2 + 2(-3) + 5 = 3-6+5 = 2
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Min: (-3,2)
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Cheers,
Stan H.
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