SOLUTION: y^2+y=(x+2)^2+y^2+3 can you help me with the vertices??

Question 542413: y^2+y=(x+2)^2+y^2+3
can you help me with the vertices??
Answer by jpg7n16(66) (Show Source): You can put this solution on YOUR website!
Ok, this problem is easier than it looks because you get to reduce the craziness out of it. If:
subtract y^2 from each side.

What that means is that you take a normal x^2 parabola, push it 2 to the left and up 3.
And parabolas only have 1 vertex. This one will be at the min, when the (x+2)^2 piece is 0. That's at x=-2. So vertex at (-2,3)
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