SOLUTION: i need to list the vertex, focus, and directrix of this parabola (x+2) = -8(y-3)^2

Question 537448: i need to list the vertex, focus, and directrix of this parabola
(x+2) = -8(y-3)^2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
i need to list the vertex, focus, and directrix of this parabola
(x+2) = -8(y-3)^2
**
Standard form of an equation for a parabola which opens leftwards: (y-k)^2=-4p(x-h), (h,k) being the (x,y) coordinates of the vertex.
..
(x+2) = -8(y-3)^2
rewrite equation
(y-3)^2=-(1/8)(x+2)
vertex:(-2,3)
Axis of symmetry: y=3
4p=1/8
p=1/32
focus:(-2-(1/32,3)=[-(65/32),3] (p units from vertex on the axis of symmetry)
directrix: x=-63/32 (a vertical line p units from vertex on the axis of symmetry)
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