SOLUTION: What is the center of the hyperbola whose equation is (x2)/4 - (y2)/9 = 1?
Algebra.Com
Question 531357: What is the center of the hyperbola whose equation is (x2)/4 - (y2)/9 = 1?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the center of the hyperbola whose equation is (x2)/4 - (y2)/9 = 1
**
Whenever you don't see h and k in the standard form of a hyperbola:
(x-h)^2/a^2-(y-k)^2/b^2=1, the center is at the origin or (0,0)
RELATED QUESTIONS
How does the graph of the hyperbola whose equation is (y2)/4 - (x2)/9 = 1 open? (answered by lwsshak3)
Classify the conic section:
1. x2 + y2 = 36
2. x2 - y2 = 36
3. 5x2 +... (answered by Edwin McCravy)
What is the center of the ellipse whose equation is (x2)/25 + (y2)/4 =... (answered by lwsshak3)
How does the graph of the hyperbola whose equation is (y2)/4 - (x2)/9 = 1 open?
A. A... (answered by ikleyn,greenestamps)
How does the graph of the hyperbola whose equation is (x2)/9 - (y2)/25 = 1 open?
A. A... (answered by Edwin McCravy)
. Find the center and radius of the circle whose equation is x2 + y2 – 4 = 0.
(answered by Alan3354)
What are the vertices of the ellipse whose equation is (x2)/9 + (y2)/36 = 1? (answered by lwsshak3)
what is the center and the equation of... (answered by ewatrrr)
What is the general form of the equation of a circle with its center at (-2, 1) and... (answered by josgarithmetic)