SOLUTION: parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the parabola

Question 530268: parabola,x^2 +6x -y +11 =0
find the vertex,focus and directrix of the parabola
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
parabola,x^2 +6x -y +11 =0
find the vertex,focus and directrix of the parabola
**
Standard form of equation for parabola: (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex.
x^2 +6x -y +11 =0
complete the square:
y=(x^2+6x+9)+11-9
y=(x+3)^2+2
Rewrite in standard form
(x+3)^2=(y-2)
Vertex: (-3,2)
4p=1
p=1/4
focus: (-3,9/4)
directrix: y=7/4
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