SOLUTION: How do I find the x-intercepts of the parabola with vertex (-3,16)and y-intercept (0,-20)

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 Question 526143: How do I find the x-intercepts of the parabola with vertex (-3,16)and y-intercept (0,-20)Answer by lwsshak3(6491)   (Show Source): You can put this solution on YOUR website!How do I find the x-intercepts of the parabola with vertex (-3,16)and y-intercept (0,-20) ** Standard equation for parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. .. Given equation: y=A(x+3)^2+16 using given point (0,-20) to solve for A -20=A(0+3)^2+16 9A=-36 A=-4 Equation of parabola: y=-4(x-h)^2+k Find x-intercepts set y=0 0=-4(x+3)^2+16 4(x+3)^2=16 (x+3)^2=4 x+3±√4=±2 x=-5 or x=-1 Ans: x-intercepts: -5 and -1