SOLUTION: I'm trying to find the asymtotes of a hyperbola equation. What is the square root of 6 over 2 times 3?

Question 507372: I'm trying to find the asymtotes of a hyperbola equation. What is the square root of 6 over 2 times 3?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I'm trying to find the asymtotes of a hyperbola equation. What is the square root of 6 over 2 times 3?
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√6/(2*3)=√6/6
leave as is, cannot be further simplified.
..
asymptotes of hyperbolas are straight lines so you can used the standard form of this equation:
y=mx+b, m=slope, b=y-intercept
The slope depends on whether hyperbola has a vertical or horizontal transverse axis. Standard form of equation for a hyperbola with horizontal transverse axis: (x-h)^2/a^2-(y-k)^2/b^2=1. For vertical transverse axis: (y-k)^2/a^2-(x-h)^2/b^2=1. Slope for a horizontal transverse axis hyperbola=�b/a and �a/b for a vertical transverse axis hyperbola. To find b, the y-intercept, use the x,y coordinates of the center thru which the asymptotes pass.
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