SOLUTION: how do you find the equation of the parabola whose vertex is (4,-11) and that passes through the points (-6,16)

Question 491703: how do you find the equation of the parabola whose vertex is (4,-11) and that passes through the points (-6,16)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do you find the equation of the parabola whose vertex is (4,-11) and that passes through the points (-6,16)
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Form: y = a(x-h)^2 + k
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h = 4 and k = -11
y = 16 when x = -6
Solve for "a":
16 = a(-6-4)^2-11
16 = a(100) - 11
27 = 100a
a = 0.27
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Equation:
y = 0.27(x-4)^2-11
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Graph:

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Chers,
Stan H.
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