# SOLUTION: I am not sure how to go about changing the following problem into standard form. I tried to do completing the square, but I'm not sure how to use it in this situation or when ther

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: I am not sure how to go about changing the following problem into standard form. I tried to do completing the square, but I'm not sure how to use it in this situation or when ther      Log On

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 Question 49056: I am not sure how to go about changing the following problem into standard form. I tried to do completing the square, but I'm not sure how to use it in this situation or when there is a coefficient other than 1 in front of x^2 and y^2. I would greatly appreciate help on how to solve the following problem. Thanks! Change the equation to standard form and name the figure. 3x^2-2y^2-12x-20y-44=0 Found 2 solutions by Nate, xerxes0212:Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website! You square the number, then multiply it by the coefficient. Answer by xerxes0212(2)   (Show Source): You can put this solution on YOUR website! 3x^2 - 2y^2 - 12x - 20y - 44 = 0 Transpose -44 to the other side. 3x^2 - 2y^2 - 12x - 20y = 44 Rearrange the terms. 3x^2 - 12x - 2y^2 - 20y = 44 Factor expressions with same variables by finding the common factor. 3(x^2 - 4x) - 2(y^2 + 10y) = 44 Use completing the squares and balance the equation (add terms to the right side) by adding the terms that were added to the left side. 3(x^2 - 4x + 4) - 2(y^2 + 10y + 25) = 44 + 3(4) - 2(25) Simplify the right side. 3(x^2 - 4x + 4) - 2(y^2 + 10y + 25) = 6 Write the perfect square trinomials as square of binomials. 3(x - 2)^2 - 2(y+ 5)^2 = 6 Make the right side equal to 1 by dividing all terms by 6. (x - 2)^2 - (y + 5)^2 --------- --------- = 1 2 3 This equation represents a hyperbola with vertical traverse axis.