SOLUTION: write the equation in standard form, then sketch the graph of the equation: x^2=y^2-6x-4y+13=36 i dont know if you can help me with the graph or not i hope so though thanks a bu

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: write the equation in standard form, then sketch the graph of the equation: x^2=y^2-6x-4y+13=36 i dont know if you can help me with the graph or not i hope so though thanks a bu      Log On

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Question 48409: write the equation in standard form, then sketch the graph of the equation: x^2=y^2-6x-4y+13=36
i dont know if you can help me with the graph or not
i hope so though
thanks a bunch
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2 - 6x - 4y + 13 = 36
x^2 - 6x + y^2 - 4y = 23
(x - 3)^2 + (y - 2)^2 = 23 + 9 + 4 = 36
(x - 3)^2 + (y - 2)^2 = 36
Center: (3,2)
Radius: 6
graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Csqrt%2836+-+%28x+-+3%29%5E2%29+%2B+2%2C-sqrt%2836+-+%28x+-+3%29%5E2%29+%2B+2%29