// End script hiding -->
SOLUTION: Explain which conic section this equation and explain how to solve it: 12x^2-18y^2-18x-12y+12=0
Algebra
->
Quadratic-relations-and-conic-sections
-> SOLUTION: Explain which conic section this equation and explain how to solve it: 12x^2-18y^2-18x-12y+12=0
Log On
Ad:
Mathway
solves algebra homework problems with step-by-step help!
Algebra: Conic sections - ellipse, parabola, hyperbola
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Quadratic-relations-and-conic-sections
Question 482542
:
Explain which conic section this equation and explain how to solve it:
12x^2-18y^2-18x-12y+12=0
Answer by
lwsshak3(11500)
(
Show Source
):
You can
put this solution on YOUR website!
Explain which conic section this equation and explain how to solve it:
12x^2-18y^2-18x-12y+12=0
***
12x^2-18y^2-18x-12y+12=0
dividing by 3 to simplify
3x^2-6y^2-6x-4y+4=0
completing the square
3(x^2-2x+1)-6(y^2+(2/3)y+1/9)=-4+3-2/3=-1-2/3=-5/3
3(x-1)^2-6(y-1/3)^2=-5/3
multiply both sides by (-1)
6(y-1/3)^2-3(x-1)^2=5/3
divide both sides by 5/3
(y-1/3)^2/(5/18)-(x-1)^2/(5/9)=1
This is an equation of a hyperbola with vertical transverse axis of the standard form:
(y-k)^2/a^2-(x-h)^2/b^2=1
For given equation:
Center:(1,1/3)
a^2=5/18
a=√(5/18)
Length of transverse axis=2a=2*√(5/18)
Vertices: (1,1/3±a), (1,1/3±√(5/18))
b^2=5/9
b=√(5/9)
Length of conjugate axis=2b=2*√(5/9)
c^2=a^2+b^2=5/18+5/9=15/18
c=√(15/18)
Foci: (1,1/3±c)=(1,1/3±√(15/18))
Slope of asymptotes=±a/b=±√(5/18)/√(5/9)=±√(1/2)=±√2/2
Equation of asymptotes:
Asymptotes are straight lines of the standard form: y=mx+b, m=slope, b=y-intercept
Asymptote with positive slope:
y=(√2/2)x+b
solving for b, using center coordinates thru which asymptotes pass
1/3=(√2/2)*1+b
b=-.3737
equation: y=.707x-.3737
..
Asymptote with negative slope:
Equation: y=-.707x+1.0403
..
Comment: As you can see, there is a whole bunch of things that can be asked about a hyperbola.