SOLUTION: Identify the x-intercepts and the axis of symmetry of y=(x-1)(x-5) and Rewrite in intercept form: y=2x^2-2x-4 thank you

Question 481379: Identify the x-intercepts and the axis of symmetry of y=(x-1)(x-5)
and
Rewrite in intercept form: y=2x^2-2x-4
thank you
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Identify the x-intercepts and the axis of symmetry of y=(x-1)(x-5)
and Rewrite in intercept form: y=2x^2-2x-4
**
y=(x-1)(x-5)
By inspection, it can be seen that the x-intercepts are 1 and 5
For y-intercepts, set x=0, then solve for y
y=-1*-5=5
..
For axis of symmetry, rewrite equation in standard form for a parabola:
y=(x-1)(x-5)=x^2-6x+5
completing the square:
y=(x^2-6x+9)+5-9
y=(x-3)^2-4
This is an equation of a parabola of standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
For given equation:
vertex: (3,4)
parabola opens upwards
so, axis of symmetry is x=3
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