SOLUTION: Can someone please help me answer these questions? Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .

Question 478978: Can someone please help me answer these questions?

Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
y^2 -2x^2 -16=0

Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
y= x^2 +3x+1
Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
x2 +y^2 =x+2

Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
x^2 +4y^2 +2x -24y +33 =0

Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
x^2 + y^2 -8x -6y +5 = 0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
y^2 -2x^2 -16=0
Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
y= x^2 +3x+1
It is in standard form:
parabola
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Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
x^2 +y^2 =x+2
(x^2-x+(1/2)^2)+y^2 = 2+(1/4)
---
(x-(1/2))^2 + y^2 = (3/2)^2
Circle
----------------

Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
x^2 +4y^2 +2x -24y +33 =0
(x^2+2x+1) + 4(y^2-6y+9) = -33+1+36
(x+1)^2 + 4(y-3)^2 = 4
[(x+1)^2/4] + (y-3)^2 = 1
Ellipse
-----------------------------

Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola .
x^2 + y^2 -8x -6y +5 = 0
Complete the square on the x and on the y terms.
Circle
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Cheers,
Stan H.

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