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Question 47865: write the equation of the axis of symetry and find the coodinates. identify the vetext as a maximum or miumum
y=3x^2-6x-4
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500)   (Show Source):
You can put this solution on YOUR website!y = 3x^2 - 6x - 4
v(-b/2a,f(x))
Since the parabola is vertical, the Axis of Symmetry is: 
Since the value of  is positive, the parabola opens upwards. The vertex is a minimum.
Answer by stanbon(48569) (Show Source):
You can put this solution on YOUR website!write the equation of the axis of symetry and find the coodinates. identify the vetext as a maximum or miumum
y=3x^2-6x-4
Put this in the form (x-h)^2 = 4p(y-k) by completing the square, as follows:
y+4+3=3(x^2-2x+1)
y+7=3(x-1)^2
(x-1)^2=(1/3)(y+7)
Axis of symmetry: x=1
Vertex (1,-7) is a minimum
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=84 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 2.52752523165195, -0.527525231651947.
Here's your graph:
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Cheers,
Stan H.
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