SOLUTION: What are the foci of the ellipse 17x2 + 8y2 = 136? show work please

Question 475259: What are the foci of the ellipse 17x2 + 8y2 = 136? show work please
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What are the foci of the ellipse 17x2 + 8y2 = 136? show work please
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17x^2+8y^2=136
divide by 136
x^2/8+y^2/17=1
This is an ellipse with vertical major axis of the standard form: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b
for given equation:
Center:(0,0)
a^2=17
b^2=8
c^2=a^2-b^2=17-8=9
c=√9=3
Foci: (0,0�c)=(0,0�3)=(0,3) and (0,-3)
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