SOLUTION: Find the equation in standard form of the hyperbola with an asymptote slope of 3/4 and foci (-2,-8) and (8,-8). a.(x-3)^2/9-(y+8)^2/16=1 b.(y-3)^2/16-(x+8)^2/9=1 c.(y+8)^2/9-(

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Question 470819: Find the equation in standard form of the hyperbola with an asymptote slope of 3/4 and foci (-2,-8) and (8,-8).
a.(x-3)^2/9-(y+8)^2/16=1
b.(y-3)^2/16-(x+8)^2/9=1
c.(y+8)^2/9-(x-3)^2/9=1
d.(x-3)^2/16-(y+8)^2/9=1
e.(x+8)^2/9-(y-3)^2/16=1

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Standard Form of an Equation of an Hyperbola is
where Pt(h,k) is a center with vertices 'a' units right and left of center.
Asymptotes passing thru the center with slope = ± b/a
foci being ± sqrt(a^2 + b^2)from center along axis of symmetry y = k

asymptote slope b/a = 3/4
foci (-2,-8) and (8,-8). c = sqrt(16+9) = 5, C(3,-8)


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