SOLUTION: Please note that graphing is not allowed to solve this. If x^2+y^2=36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y?

Question 458999: Please note that graphing is not allowed to solve this.
If x^2+y^2=36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If x^2 + y^2 = 36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y?
Get rid of the annoying fraction in the 2nd equation

multiply by 64 and we have
4(x^2) + y^2 = 64
:
Use elimination with the 1st equation just as it is
4x^2 + y^2 = 64
x^2 + y^2 = 36
----------------subtraction eliminates y^2, find x^2
3x^2 = 28
x^2 =
x = =
:
Find y, replace x^2 with in the 1st equation
+ y^2 = 36
y^2 = 36 -
y^2 = -
y =
y = =
:

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