SOLUTION: What conic is described by the equation 8x^2 + 8y^2 - 4x + y = 0. please show steps. Thank you.

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 Question 457431: What conic is described by the equation 8x^2 + 8y^2 - 4x + y = 0. please show steps. Thank you.Answer by lwsshak3(6513)   (Show Source): You can put this solution on YOUR website!What conic is described by the equation 8x^2 + 8y^2 - 4x + y = 0. please show steps. .. 8x^2 + 8y^2 - 4x + y = 0 completing the square 8(x^2-x/2+1/16)+8(y^2+y/8+1/256)=1/2+1/32=16/32+1/32=17/32 8(x-1/4)^2+8(y+1/16)^2=17/32 divide by 8 (x-1/4)^2+(y+1/16)^2=17/256 This equation is a circle with center at (1/4, -1/16) and radius=sqrt(17/256) see graph below as a visual check on the answer. .. y=(17/256-(x-1/4)^2)^.5-1/16