Question 456940: find the standard form of each equation by completing the square then identify the conic section of x^2+y^2-4x+6y-12=0 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! find the standard form of each equation by completing the square then identify the conic section of x^2+y^2-4x+6y-12=0
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(x^2-4x+4)+(y^2+6y+9)=12+4+9=25
(x-2)^2+(x+3)^2=25
This is a circle with center at (2,-3) with radius=5
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