SOLUTION: What would be the eqaution of a circle containging the points (0,-2) and (6,6) and whose center is on the line x - y = 1?

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Question 456905: What would be the eqaution of a circle containging the points (0,-2) and (6,6) and whose center is on the line x - y = 1?
Answer by spacesurfer(12)   (Show Source): You can put this solution on YOUR website!
The equation of the line is rewritten. Hence a point on the line is (x, x-1). Let's say the center is at (x, x-1). Then the distance between (6,6) and the center = radius = distance between center and (0,-2). Using the point to point distance formula, we have

This is the same as
The solution is x = 3. Hence, the center is at (3,2).
The radius = 5 since .
So, the equation of the circle is

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