# SOLUTION: Write an equation for each ellipse described below: the endpoints of the major axis are at (10,2) and (-8,2). The foci are at (6,2) and (-4,2). I have found that the center is

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Write an equation for each ellipse described below: the endpoints of the major axis are at (10,2) and (-8,2). The foci are at (6,2) and (-4,2). I have found that the center is       Log On

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 Algebra: Conic sections - ellipse, parabola, hyperbola Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 454540: Write an equation for each ellipse described below: the endpoints of the major axis are at (10,2) and (-8,2). The foci are at (6,2) and (-4,2). I have found that the center is at (1,2), but this may be wrong.Answer by lwsshak3(6519)   (Show Source): You can put this solution on YOUR website!Write an equation for the ellipse described below: the endpoints of the major axis are at (10,2) and (-8,2). The foci are at (6,2) and (-4,2). I have found that the center is at (1,2), but this may be wrong. .. Standard form of ellipse with horizontal major axis: (x-h)^2/a^2+(y-k)^2/b^2=1, (a>b), with (h,k) being the (x,y) coordinates of the center. Standard form of ellipse with vertical major axis: (x-h)^2/b^2+(y-k)^2/a^2=1, (a>b), with (h,k) being the (x,y) coordinates of the center. The difference between the two forms is the interchange of a^2 and b^2. .. Major axis and foci located on the line, y=2, shows that this ellipse has a horizontal major axis, with center at (1,2) as you correctly figured out. Center (1,2) length of major axis=18=2a a=9 a^2=81 2c=10 c=5 c^2=25 c^2=a^2-b^2 b^2=a^2-c^2=81-25=56 .. Equation: (x-1)^2/81+(y-2)^2/56=1 See the graph below for a visual check on the answers. .. y=(56-56(x-1)^2/81)^.5+2