Question 454238: (x+6)^2_______(y-4)^2
-------------- + ---------------- = 1
___12__________ 16
this is a ellipse formula. find the vertices and foci coordintes.
(the dash marks are fractions, the underscores are nothing, it wouldnt let me format it properly.
THANKS FOR TRYING!
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 
Use braces { and }, 3 on each end, to format.
Long axis is "vertical", parallel to the y-axis (16>12)
Center at (-6,4)
Distance from center to foci = sqrt(16 - 12) = 2
Foci at (-6,2) and (-6,6)
-----------------------
Vertices at center +/- sqrt(16) vertically --> (-6,0) & (-6,8)
Vertices at center +/- sqrt(12) horizontally
--> (-6-sqrt(12),4) & (-6+sqrt(12),4)
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