SOLUTION: Formula for an ellipse= (x+1)^24(y+3)^2=1 what are the vertices and foci of this ellipse

Question 454235: Formula for an ellipse= (x+1)^24(y+3)^2=1
what are the vertices and foci of this ellipse
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Formula for an ellipse= (x+1)^24(y+3)^2=1
what are the vertices and foci of this ellipse
-------------
Do you mean (x+1)^2 + 4(y+3)^2=1 ?
(x+1)^2/1 + (y+3)^2/0.25 = 1
a^2 = 1, b^2 = 1/4
Center at (-1,-3), long axis parallel to the x-axis
-----------------
Distance to foci = sqrt(a^2 - b^2) = sqrt(0.75)
Foci at (-1-sqrt(0/75),-3) and (-1+sqrt(0.75,-3)
----------
Vertices 1 unit from center parallel to x-axis and 1/2 unit vertical
--> (-2,-3) and (0,-3)
and (-1,-3.5) and (-1,-2.5)
RELATED QUESTIONS
x^2/16+y^2/9=1 What is the foci and vertices of this ellipse... (answered by lwsshak3)

Find the center, vertices and foci of the following ellipse: (x + 3)^2/9 + (y +... (answered by funmath)

find the foci and vertices of the ellipse. x^2 y^2 --+ --=1 144... (answered by lwsshak3)

Find center, vertices, and foci of the ellipse:... (answered by lwsshak3)

an ellipse's foci (0,�1) and vertices (0,�2). what is the eccentricity of the... (answered by josgarithmetic)

(x+6)^2_______(y-4)^2 -------------- + ---------------- = 1 ___12__________ 16 this (answered by Alan3354)

The problem is: identify the vertices, co-vertices, and foci of the ellipse:... (answered by richwmiller)

Graph the equation. Identify the vertices, co vertices, and foci of the ellipse.... (answered by lwsshak3)

x^2/25+y^2/16=1 what are its vertices,foci,eccentricty of the ellipse? length of major (answered by ikleyn)