SOLUTION: Find the standard equation with focus: (-2,0) and Directrix: x=4 (y-k)2 = -4p(x-h) This is as far as I have gotten. I think that the vertex is (1,0)

Question 449489: Find the standard equation with focus: (-2,0) and Directrix: x=4
(y-k)2 = -4p(x-h) This is as far as I have gotten. I think that the vertex is (1,0)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the standard equation with focus: (-2,0) and Directrix: x=4
..
Since the focus is to the left of the directrix, this is a parabola which opens leftward with axis of symmetry being the x-axis or y=0. Standard form for this parabola is:
y^2=-4px
Distance between focus on the axis of symmetry=6
p=1/2 this distance = 3
vertex on the axis of symmetry is at (1,0) (located halfway between focus and directrix on axis of symmetry)
Equation of given parabola:
y^2=-12(x-1)
see the graph below for a visual representation of the equation for given parabola.
y=(-12(x-1))^.5

RELATED QUESTIONS
Could someone please help me with writing a conic equation in standard form? The... (answered by josgarithmetic,Natolino1983)

Hi! I have a problem that asks: "Find the focus and directrix of the parabola from the... (answered by lwsshak3)

Find the vertex, focus and directrix and sketch the graph of the parabola from the... (answered by Edwin McCravy)

Find an equation of the parabola that has vertex (1,2) and focus (-1,2). I think that... (answered by scott8148)

Is this correct: What is the equation of a parabola with vertex (0,0) and focus (0,4)? (answered by solver91311,Edwin McCravy)

v=(4,2) Directrix : y=5 (this is the given information) I get focus is 4,1 and this... (answered by lwsshak3)

Derive the equation of the parabola with a focus at (2, −1) and a directrix of y =... (answered by ewatrrr)

Please help me with this problem also: Find the coordinates of the focus and the... (answered by josgarithmetic)