SOLUTION: Convert each equation to the standard form of conic section y^2+6y-x=0 x^2-y^2-6x+13=0

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 Algebra: Conic sections - ellipse, parabola, hyperbola Solvers Lessons Answers archive Quiz In Depth

 Question 448928: Convert each equation to the standard form of conic section y^2+6y-x=0 x^2-y^2-6x+13=0 Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, Converting each equation to the standard form of conic section y^2+6y-x=0 |Parabola opening right or left x = y^2+6y x = (y+3)^2 - 9 |Vertex form V(-9,-3) x^2-y^2-6x+13=0 |Hyperbola opening up and down (multiplying thru by -1) y^2 - x^2 + 6x -13 = 0 y^2 -[(x-3)^2 -9] - 13 = 0 y^2 -(x-3)^2 +9 - 13 = 0 y^2 - (x-3)^2 = 4 ```