SOLUTION: please solve this and graph: 36y^2 + 216y - 4x^2 - 40x +80 = 0 thanks so much.

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Question 448875: please solve this and graph: 36y^2 + 216y - 4x^2 - 40x +80 = 0
thanks so much.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
36y^2 + 216y - 4x^2 - 40x +80 = 0
[36(y+3)^2 - 9] -4[(x+5)^2 -25] = -80 |Multiplying thru by -1
36(y+3)^2 - 324 -4(x+5)^2 + 100 = -80
36(y+3)^2 -4(x+5)^2 = 144

Hyperbola opening up and down: C(-5,-3) Vertices (-5,-1) and (-5,-5

Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola is where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
where Pt(h,k) is a center with vertices 'b' units up and down from center.
Using the vertex form of a parabola opening up or down,
where(h,k) is the vertex
The standard form is , where the focus is (h,k + p)
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