SOLUTION: what is the center of this ellipse? x2+4y2+12x-32y+96=0

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Question 448544: what is the center of this ellipse? x2+4y2+12x-32y+96=0
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Standard Form of an Equation of an Ellipse is where Pt(h,k) is the center
and a and b are the respective vertices distances from center.
x^2+4y^2+12x-32y+96=0
(x+6)^2 - 36 + 4(y-4)^2 - 4*16 + 96 = 0
(x+6)^2 + 4(y-4)^2 = 4
Center (-6,4)
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