SOLUTION: The graph of the equation below is a circle. What is the length of the radius of the circle?(x - 6)2 + (y + 5)2 = 152

Algebra.Com
Question 448264: The graph of the equation below is a circle. What is the length of the radius of the circle?(x - 6)2 + (y + 5)2 = 152
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
The equation is in the same form as that of a circle (x-h)^2 + (y-k)^2 = r^2, with r^2 = 152. This implies that r = sqrt(152).
RELATED QUESTIONS

The graph of the equation below is a circle. What is the length of the radius of the... (answered by stanbon)
The graph of the equation given below is a circle. What is the length of the radius of... (answered by Alan3354)
The graph of the equation below is a circle. What is the length of the radius of the... (answered by solver91311,josgarithmetic)
What is the length of the radius of the circle? (x - 6)2 + (y + 5)2 = 152 please help... (answered by lwsshak3)
The equation below is a circle. What is the x-coordinate of the center of the circle?... (answered by ewatrrr)
The graph of the equation below is a circle. What is the length of the radius of the... (answered by MathLover1)
The equation below is a circle. What is the x-coordinate of the center of the circle?... (answered by Fombitz)
The equation below is a circle. What is the y-coordinate of the center of the circle?... (answered by Alan3354)
the equation for the circle below ia x^2+y^2=64. what is the length of the circle... (answered by lynnlo)