SOLUTION: x^2+y^2+2x+2y+1=0

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Question 447701: x^2+y^2+2x+2y+1=0
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
it’s a circle, and the given equation is of the form


where (,) is the

and , so the center is at (-1,-1)

intercept on

substituting the values

so, it axis

intercept on

substituting the values

so, it axis


Solved by pluggable solver: PLOT any circle and describe it

Diameter: .
Area:
Perimeter:







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