SOLUTION: Solve the system of equations: y-3x-2=0 x^2+y^2=4

Question 447021: Solve the system of equations: y-3x-2=0
x^2+y^2=4
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
y-3x-2=0
y=3x+2
x2+(3x+2)2-4=0
x2+9x2+12x+4-4=0
10x2+12x=0
10x2=-12x
10x=-12
x=-12/10=-6/5
y=-8/5

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=144 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0, -1.2. Here's your graph:

Throwing out 0, we get x=-6/5..
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