SOLUTION: Given that the equation of a parabola is y^2+4y-8x+20=0 find the equation in the form (y-k)^2=4a(x-h).

Algebra.Com
Question 446616: Given that the equation of a parabola is y^2+4y-8x+20=0 find the equation in the form (y-k)^2=4a(x-h).
Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!
Given that the equation of a parabola is y^2+4y-8x+20=0
find the equation in the form (y-k)^2=4a(x-h).
y² + 4y - 8x + 20 = 0

Isolate the terms in y on the left side:

          y² + 4y = 8x - 20

Multiply the coefficient of y, which is 4, by 1/2,
getting 2.  Then square 2. getting 4, and add +4
to both sides:

      y² + 4y + 4 = 8x - 20 + 4

Factor the left side, combine terms on the right:

   (y + 2)(y + 2) = 8x - 16

Write the left side as the square of a binomial
and factor out 8 on the right:

         (y + 2)² = 8(x - 2)

Write the 8 as 4*2

         (y + 8)² = 4*2(x - 2)

Compare to 

         (y - k)² = 4*a(x - h)

So -k = +8 or k = -8
   -h = -2 or h = 2
    a = 2

Edwin





RELATED QUESTIONS

Find the equation of the parabola that concaves down in the form of y = a(x-h)^2 + k,... (answered by josgarithmetic,greenestamps)
Show that the quadratic function {{{y=ax^2+bx+c}}} can be written in the form... (answered by fcabanski)
) Write the equation y=x^2-8x in the form y=a(x-h)^2... (answered by Alan3354)
I beg you, please help meeee Find the equation of the parabola determined by the given (answered by josgarithmetic)
Find the equation of the parabola determined by the given conditions Axis vertical and... (answered by josgarithmetic)
Find an equation in standard form of the parabola described. Vertex at (−2, 4); passes (answered by MathLover1)
Find an equation in standard form of the parabola described. Vertex at (−3, −3);... (answered by MathLover1)
find an equation in the form y-k=a(x-h)^2 for the parabola with axis of symmetry x=-2and... (answered by lwsshak3)
a Parabola has a vertex (-1,5) and contains the point (2,-4). Write an equation of the... (answered by nerdybill)