SOLUTION: x^2-18x-y^2+12y=19, find the center and vertices

Algebra.Com
Question 445932: x^2-18x-y^2+12y=19, find the center and vertices
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi, Note:
Standard Form of an Equation of an Hyperbola opening right and left is

where Pt(h,k) is a center with vertices 'a' units right and left of center.
x^2-18x-y^2+12y=19
(x-9)^2 -81 -[(y-6)^2-36] = 19
(x-9)^2 -81 -(y-6)^2+36 = 19
(x-9)^2 -(y-6)^2 = 64
C(9,6) with vertices V(1,6) and V(17,6)


RELATED QUESTIONS

Classify the conic section and write its equation in standard form. 1) 4x^2 + y^2 -... (answered by lynnlo)
Find the center and radius of the circle... (answered by solver91311)
how to find Find the center, vertices, foci and asymptotes of this equation {{{ 9x^2... (answered by josgarithmetic)
Find the center, vertices, foci and eccentricity of the ellipse 6x^2 + 2y^2 + 18x - 10y + (answered by ikleyn)
Find the center, the vertices, and the foci of the ellipse... (answered by lwsshak3)
Find the center and radius of the circle with the equation x^2 + 18x = y - y^2 -... (answered by scott8148)
Find the center and the radius of the circle show your work... (answered by ewatrrr)
Find the center, foci, vertices, and asymptotes of the hyperbola. x^2 - y^2 = 8(x-y)... (answered by ewatrrr)
6. find the center, vertices, and foci of the ellipse with the following equation: (answered by lynnlo)