Hi

Find the vertex and focus of the parabola.

y^2 = 36x – 216

Note: vertex form of a parabola,  where(h,k) is the vertex

  x = (1/36)y^2 + 6  V( 6,0) Parabola opening right a = 1/36 > 0

Note: standard form is , where  the focus is (h + p, k)

 y^2 = 36(x-6)   4p = 36  p = 9

focus(6+9,0)or (15,0)







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