SOLUTION: Find the foci of the ellipse (X + 3)^2/25 + (Y - 2)^2/9 = 1?

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Question 441913: Find the foci of the ellipse (X + 3)^2/25 + (Y - 2)^2/9 = 1?
Answer by ewatrrr(10682) About Me  (Show Source):
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Hi

the foci of the ellipse (X + 3)^2/25 + (Y - 2)^2/9 = 1

Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+

where Pt(h,k) is the center and a and b  are the respective vertices distances from center.

  Center(-3,2)   f = sqrt%2825-9%29+=+sqrt%2816%29 = 4

foci are (-7,2) and (1,2)

 









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