SOLUTION: Obtain an equation of the conic described, then graph by hand: Here is the problem: Hyperbola, vertices at (-2,0) and (2,0), focus at (4,0) THANK YOU.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Obtain an equation of the conic described, then graph by hand: Here is the problem: Hyperbola, vertices at (-2,0) and (2,0), focus at (4,0) THANK YOU.      Log On


   



Question 441857: Obtain an equation of the conic described, then graph by hand:
Here is the problem: Hyperbola, vertices at (-2,0) and (2,0), focus at (4,0)
THANK YOU.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi, Note:
Standard Form of an Equation of an Hyperbola opening right and left is
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1
where Pt(h,k) is a center with vertices 'a' units right and left of center.
vertices at (-2,0) and (2,0), focus at (4,0) Center( 0,0)
x%5E2%2F2%5E2+-+y%5E2%2Fb%5E2+=+1 f = 4 = sqrt%282%5E2+%2B+b%5E2%29 b^2 = 12
x%5E2%2F4+-+y%5E2%2F12+=+1





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