SOLUTION: Graph the ellipse. Label the major axis, minor axis, and the foci. Show the graph. 9x^2+25y^2+36x-150y+36=0

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Question 440998: Graph the ellipse. Label the major axis, minor axis, and the foci. Show the graph.
9x^2+25y^2+36x-150y+36=0

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
9x² + 25y² + 36x - 150y + 36 = 0

     9x² + 36x + 25y² - 150y = -36

    9(x² + 4x) + 25(y² - 6y) = -36

Multiply the cofficient of x, which is 4, by 1/2, get 2,
square 2, get +4.  Add + 4 inside the first parentheses,
which amounts to adding 9*4 or 36 to the left side, so
add + 36 to the right side:

 9(x² + 4x + 4) + 25(y² - 6y) = -36 + 36

Multiply the cofficient of y, which is -6, by 1/2, get -3,
square -3, get +9.  Add + 9 inside the second parentheses,
which amounts to adding 25*9 or 225 to the left side, so
add + 225 to the right side:

  9(x² + 4x + 4) + 25(y² - 6y + 9) = -36 + 36 + 225

Factor the expressions in parentheses

9(x + 2)(x + 2) + 25(y - 3)(y - 3) = 225

Write the factorizations as perfect squares:

            9(x + 2)² + 25(y - 3)² = 225

Get a 1 on the right by dividing every term by 225

            9(x + 2)²   25(y - 3)²   225
            ————————— + —————————— = ———
               225         225       225

Simplify:

               (x + 2)²   (y - 3)²   
               ———————— + ———————— = 1
                  25         9       
 
Compare to 

               (x - h)²   (y - k)²   
               ———————— + ———————— = 1
                  a²         b²

because a² > b² in an ellipse

a² = 25 so a = 5
b² = 9 so b = 3
h = -2, k = 3

center = (h,k) = (-2,3)

Plot the center:

 
 
The major axis is 2a or 2(5) or 10 units long, is horizontal
and has the center as its midpoint.  We draw this major axis
in green: 



The minor axis is 2b or 2(3) or 6 units long, is vertical
and also has the center as its midpoint.  We draw this minor axis
in green also:



We draw in the ellipse:



The vertices are the endpoints of the major axis, (-7,3) and (3,3)

The co-vertices are the endpoints of the minor axis, (-2,0) and (-2,6)

The foci are two points inside the ellips on the major axis, which are
c units from the center on each side of the center. We calculate c from
this equation

c² = a² - b²
c² = 5² - 3²
c² = 25 - 9
c² = 16
c = 4 

So the foci are (-6,3) and (2,3)





Edwin

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