Hi



a. Find the co-ordinates of the vertex and the focus of the parabola 

 x2=4(x+y)

 x^2 - 4x = 4y

 (x-2)^2 - 4 = 4y  OR (x-2)^2 = 4(y+1)

Using the vertex form of a parabola,  where(h,k) is the vertex

 1/4(x-2)^2 - 1 = y   Vertex (2,-1)

 The standard form is , where  the focus is (h,k + p) 

                        (x-2)^2 = 4(y+1)  4p = 4 , p = 1 focus(2,0)





 

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