SOLUTION: graph the equation, then choose the correct coordinates of the foci. y^2 = 5x^2 + 25

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: graph the equation, then choose the correct coordinates of the foci. y^2 = 5x^2 + 25      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 43949: graph the equation, then choose the correct coordinates of the foci.
y^2 = 5x^2 + 25
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E2+=+5x%5E2+%2B+25
y%5E2+-+5x%5E2+=+25
%28y%5E2%29%2F25+-+%28x%5E2%29%2F5+=+1
Center: (0,0)
Transverse Axis: vertical
a = 5
b = sqrt%285%29
c%5E2+=+a%5E2+%2B+b%5E2
c+=+sqrt%2825+%2B+5%29
c+=+sqrt%2830%29
Vertex: (0,5) and (0,-5)
Foci: (0,sqrt%2830%29) and (0,-sqrt%2830%29)
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%285x%5E2+%2B+25%29%2C+-sqrt%285x%5E2+%2B+25%29+%29+