SOLUTION: what is the center, foci, and asymptotes for the conic? x^2/16-y^2/25=1

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Question 438565: what is the center, foci, and asymptotes for the conic?
x^2/16-y^2/25=1

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Standard Form of an Equation of an Hyperbola opeing right and left is

where Pt(h,k) is a center with vertices 'a' units right and left of center.
x^2/16-y^2/25=1 C(0,0) with vertices V(-4,0) and V(4,0) - the x-intercepts
Foci(c=: F(-6.4,0) and F(6.4,0)
Asymptotes: y = ± (5/4)x

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