SOLUTION: I need to graph this circle. x^2+y^2+4x-8y-5=0

Question 438023: I need to graph this circle.
x^2+y^2+4x-8y-5=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I need to graph this circle.
x^2+y^2+4x-8y-5=0
..
x^2+y^2+4x-8y-5=0
completing the square
(x^2+4x+4)+(y^2-8y+16)=0+4+16=20
Equation:
(x+2)^2+(y-4)^2=20
This is a circle with center at (-2/4) with a radius of sqrt(20)=4.47..
see graph below:
..
y=4+((20-(x+2)^2))^.5

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