SOLUTION: 1.what are the foci of the graph x^2/40-y^2/81=1
2.what are the foci of the graph 4x^2-9y^2=36
3.the equation 3x^2-6y^2=6 represents which conic section?
4.write an equation for
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Question 437329: 1.what are the foci of the graph x^2/40-y^2/81=1
2.what are the foci of the graph 4x^2-9y^2=36
3.the equation 3x^2-6y^2=6 represents which conic section?
4.write an equation for a parabola in which the set of all points in the plane are equidistant from the focus and line. F(-2,0); x=2
5.write an equation of a parabola that opens upward,has a vertex at the origin,and a focus at (0,1).
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
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3. There is an 
term AND a 
term -- therefore NOT a parabola. The coefficient on the term is different than the coefficient on the term -- therefore NOT a circle. The sign on the term is different than the sign on the term -- therefore NOT an ellipse. Therefore it is a hyperbola.
John
My calculator said it, I believe it, that settles it
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