SOLUTION: Find the center of a circle with equation: x^2 + y^2 - 6x + 4y - 4 = 0

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Question 436864: Find the center of a circle with equation: x^2 + y^2 - 6x + 4y - 4 = 0
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the center of a circle with equation: x^2 + y^2 - 6x + 4y - 4 = 0
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Complete the squares to make it standard form,
where (h,k) is the center


(x-3)^2 + (y+2)^2 = 17
Center at (3,-2)

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