# SOLUTION: (x-2)^2/9+(y-3)^2/36=1 y= -1/2x+4 the first equation needs to be written so that it has a y=

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: (x-2)^2/9+(y-3)^2/36=1 y= -1/2x+4 the first equation needs to be written so that it has a y=      Log On

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Question 436202: (x-2)^2/9+(y-3)^2/36=1
y= -1/2x+4
the first equation needs to be written so that it has a y=

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(x-2)^2/9+(y-3)^2/36=1
y= -1/2x+4
the first equation needs to be written so that it has a y=
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Sub for y in the 1st eqn and multiply thru by 36

 Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) Quadratic equation (in our case ) has the following solutons: For these solutions to exist, the discriminant should not be a negative number. First, we need to compute the discriminant : . Discriminant d=9792 is greater than zero. That means that there are two solutions: . Quadratic expression can be factored: Again, the answer is: 4.910427500436, -0.910427500435996. Here's your graph:

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