SOLUTION: (x-2)^2/9+(y-3)^2/36=1 y= -1/2x+4 the first equation needs to be written so that it has a y=
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-> SOLUTION: (x-2)^2/9+(y-3)^2/36=1 y= -1/2x+4 the first equation needs to be written so that it has a y=
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Algebra: Conic sections - ellipse, parabola, hyperbola
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Question 436202
:
(x-2)^2/9+(y-3)^2/36=1
y= -1/2x+4
the first equation needs to be written so that it has a y=
Answer by
Alan3354(30993)
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(x-2)^2/9+(y-3)^2/36=1
y= -1/2x+4
the first equation needs to be written so that it has a y=
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Sub for y in the 1st eqn and multiply thru by 36
Solved by
pluggable
solver:
SOLVE quadratic equation (work shown, graph etc)
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
Discriminant d=9792 is greater than zero. That means that there are two solutions:
.
Quadratic expression
can be factored:
Again, the answer is: 4.910427500436, -0.910427500435996. Here's your graph:
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