SOLUTION: Given the equation 3x^2-42x+6y+147=0
find vertex, if parabola opens (up,down,left, or right), and focus
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Question 435039: Given the equation 3x^2-42x+6y+147=0
find vertex, if parabola opens (up,down,left, or right), and focus
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Transform the equation in the standard form,
,
=> =>
From the last expression of the parabola,s equation we have: the vertex is the
point (7, 0) and the focus will be the point: [4c=-2 => c=-1/2],(7, -1/2).
Done.
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