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put 4x^2-9y^2=-1 in standard form and graph
Standard form of hyperbola: (x-h)^2/a^2-(y-k)^2/b^2=1 (for horizontal transverse axis)
(y-k)^2/a^2-(x-h)^2/b^2=1 (for vertical transverse axis)
This is a hyperbola with center at (0,0) and a vertical transverse axis. (curve opens up and down)
see graph of given hyperbola below: