# SOLUTION: put 4x^2-9y^2=-1 in standard form and graph

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 433027: put 4x^2-9y^2=-1 in standard form and graphAnswer by lwsshak3(6505)   (Show Source): You can put this solution on YOUR website!put 4x^2-9y^2=-1 in standard form and graph .. Standard form of hyperbola: (x-h)^2/a^2-(y-k)^2/b^2=1 (for horizontal transverse axis) (y-k)^2/a^2-(x-h)^2/b^2=1 (for vertical transverse axis) 4x^2-9y^2=-1 9y^2-4x^2=1 y^2/(1/9)-x^2/(1/4)=1 This is a hyperbola with center at (0,0) and a vertical transverse axis. (curve opens up and down) a^2=1/9 a=1/3 b^2=1/4 b=1/2 see graph of given hyperbola below: .. y=+-((1+4x^2)/9)^.5