SOLUTION: Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over.

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over.      Log On

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Question 43224This question is from textbook algebra and trigonometry with analytic geometry
: Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over.This question is from textbook algebra and trigonometry with analytic geometry

Answer by AnlytcPhil(1278) About Me  (Show Source):
You can put this solution on YOUR website!
Give the equation for the circle with center
C(3,-2) and radius 4. I came out with
(x-3)^2+(y-2)^2=16. But I'm not sure if I
worked it our right. thanks for looking it 
over.

You missed one sign

(x - h)² + (y - k)² = r²

h = 3, k = -2

[x - (3)]² + [y - (-2)]² = (4)²

[x - 3]² + [y + 2]² = 16

(x - 3)² + (y + 2)² = 16

To do it quickly just remember
to change both signs of the
coordinates of the center.



Edwin