# SOLUTION: Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over.

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over.      Log On

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 Question 43224This question is from textbook algebra and trigonometry with analytic geometry : Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over.This question is from textbook algebra and trigonometry with analytic geometry Answer by AnlytcPhil(1278)   (Show Source): You can put this solution on YOUR website!```Give the equation for the circle with center C(3,-2) and radius 4. I came out with (x-3)^2+(y-2)^2=16. But I'm not sure if I worked it our right. thanks for looking it over. You missed one sign (x - h)² + (y - k)² = r² h = 3, k = -2 [x - (3)]² + [y - (-2)]² = (4)² [x - 3]² + [y + 2]² = 16 (x - 3)² + (y + 2)² = 16 To do it quickly just remember to change both signs of the coordinates of the center. Edwin```